The Ultimate Math Game !! [{COME CHECK IT OUT!}]

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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby ZoruaLuhansk » Sun May 19, 2019 10:28 am

DestructionII wrote:https://prnt.sc/nqkuc3

What is the value of tangent of A SIMPLIFIED according to the image above?

Consider 34 as the hypotenuse, 16 as the opposite, and 30 as the adjacent side.

8/15

see 2 posts above
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby DestructionII » Sun May 19, 2019 10:43 am

ZoruaLuhansk wrote:look at the number sqrt(2)^sqrt(2)
if it is rational, we've solved our problem
if it is irrational, then (sqrt(2)^sqrt(2))^sqrt(2) = sqrt(2)^2 = 2 does

If in triangle ABC, AB = 2sqrt(2), BC = 7, and AC = 4sqrt(2), what is the length of the median from A to BC?


Forgot to answer this one, oops lol.

I don't quite know this one, but I think you gotta find the value of: 2sqrt(2)+7, then find the midpoint of that value, so I'm assuming the answer is 4.914 - Oops if I got that wrong
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby ZoruaLuhansk » Sun May 19, 2019 11:12 am

DestructionII wrote:
ZoruaLuhansk wrote:look at the number sqrt(2)^sqrt(2)
if it is rational, we've solved our problem
if it is irrational, then (sqrt(2)^sqrt(2))^sqrt(2) = sqrt(2)^2 = 2 does

If in triangle ABC, AB = 2sqrt(2), BC = 7, and AC = 4sqrt(2), what is the length of the median from A to BC?


Forgot to answer this one, oops lol.

I don't quite know this one, but I think you gotta find the value of: 2sqrt(2)+7, then find the midpoint of that value, so I'm assuming the answer is 4.914 - Oops if I got that wrong

Suppose you have 2 copies of triangle ABC
if you rotate the second one 180 degrees and stick the two BC's together, you get a paralellogram
In a paralellogram, the sum of the squares of the sides is equal to the sum of the squares of the diagonals
one diagonal has length 7, the other has length 2*the median we want
2*AB^2 + 2*AC^2 = BC^2 + (2x)^2
16 + 64 = 49 + (2x)^2
(2x)^2 = 31
x = sqrt(31)/2

Suppose p(x) is the product of all of the factors of x. For example, p(6) = 1 * 2 * 3 * 6 = 36.
If p(p(p(p(10)))) = 10^n, what is the largest prime factor of n?
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby DestructionII » Sun May 19, 2019 11:26 am

I dunno

Your father went to Farmer's Market to buy apples and oranges.

1. He bought each apple for $1.50 and each orange for $1.25.
2. He bought more than 10 fruits and spent a total of no more than $25.

What is the system of inequalities that contain two variables, and can be used to determine how much of each fruit he bought?
Additionally, where is the shaded area of the graph going to be when this system of inequalities is graphed?
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby Multiuniverse » Sun May 19, 2019 11:33 am

DestructionII wrote:I dunno

Your father went to Farmer's Market to buy apples and oranges.

1. He bought each apple for $1.50 and each orange for $1.25.
2. He bought more than 10 fruits and spent a total of no more than $25.

What is the system of inequalities that contain two variables, and can be used to determine how much of each fruit he bought?
Additionally, where is the shaded area of the graph going to be when this system of inequalities is graphed?


This is not how you play this
If you cant answer then wait for someone who can or if no one turns up for like maybe a week then you can post

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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby GMallow » Sun May 19, 2019 11:34 am

DestructionII wrote:I dunno

Your father went to Farmer's Market to buy apples and oranges.

1. He bought each apple for $1.50 and each orange for $1.25.
2. He bought more than 10 fruits and spent a total of no more than $25.

What is the system of inequalities that contain two variables, and can be used to determine how much of each fruit he bought?
Additionally, where is the shaded area of the graph going to be when this system of inequalities is graphed?

x+y>10
1.5x+1.25y<25

On the top side of the "X"

Suppose the x values: 1, 2, 3, 4, 5
Suppose the f(x) values: 2, 9, 18, 29, 42

What is the secondary difference and the quadratic equation going to be?
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby DestructionII » Sun May 19, 2019 11:50 am

Multiuniverse wrote:
This is not how you play this
If you cant answer then wait for someone who can or if no one turns up for like maybe a week then you can post


News flash: Idgad lmao

Anyhoo,
GMallow wrote:
Suppose the x values: 1, 2, 3, 4, 5
Suppose the f(x) values: 2, 9, 18, 29, 42

What is the secondary difference and the quadratic equation going to be?


sec diff: 2

f(0)= -5
equation: x^2+2x-5


How do we know when a linear regression forecast/prediction is accurate? In what relation does it have with MAE (Mean Absolute Error) and RMSE?
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby Multiuniverse » Sun May 19, 2019 12:22 pm

Wow
That's just mean

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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby ZoruaLuhansk » Sun May 19, 2019 12:56 pm

I'd still appreciate it if anyone else wants to solve my problem
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby Chemist1422 » Sun May 19, 2019 1:07 pm

ZoruaLuhansk wrote:I'd still appreciate it if anyone else wants to solve my problem

Geometry is my worst subject
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby Multiuniverse » Sun May 19, 2019 1:42 pm

ZoruaLuhansk wrote:
DestructionII wrote:
ZoruaLuhansk wrote:look at the number sqrt(2)^sqrt(2)
if it is rational, we've solved our problem
if it is irrational, then (sqrt(2)^sqrt(2))^sqrt(2) = sqrt(2)^2 = 2 does

If in triangle ABC, AB = 2sqrt(2), BC = 7, and AC = 4sqrt(2), what is the length of the median from A to BC?


Forgot to answer this one, oops lol.

I don't quite know this one, but I think you gotta find the value of: 2sqrt(2)+7, then find the midpoint of that value, so I'm assuming the answer is 4.914 - Oops if I got that wrong

Suppose you have 2 copies of triangle ABC
if you rotate the second one 180 degrees and stick the two BC's together, you get a paralellogram
In a paralellogram, the sum of the squares of the sides is equal to the sum of the squares of the diagonals
one diagonal has length 7, the other has length 2*the median we want
2*AB^2 + 2*AC^2 = BC^2 + (2x)^2
16 + 64 = 49 + (2x)^2
(2x)^2 = 31
x = sqrt(31)/2

Suppose p(x) is the product of all of the factors of x. For example, p(6) = 1 * 2 * 3 * 6 = 36.
If p(p(p(p(10)))) = 10^n, what is the largest prime factor of n?


p(x) would be x^(no. of factor/2). In the case that no. of factor is odd minus that by 1 then times the whole thing by x (because the odd one is sqrt(x))

Therefore since 10 has 4 factors (1, 2, 5, 10), p(10) is 10^(4/2) = 10^2
p(p(10)) would be p(100). 100 has 9 factors. Therefore p(100) is 100^(8/2) x 10 = 10^9
p(p(p(10)) would be p(10^9). 10^9 has ? factors

I got this far then got stuck at how many factors 10^9 has
I could probably manually do it by matching 5^9 and 2^9 but cba

I hate number theory and geometry
Also statistics

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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby dyaomaster » Sun May 19, 2019 2:29 pm

Hint: for a number x = 2^a * 3^b * 5^c * 7^d * ..., the number of factors is (a+1)(b+1)(c+1)(d+1)...
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby Multiuniverse » Sun May 19, 2019 2:36 pm

dyaomaster wrote:Hint: for a number x = 2^a * 3^b * 5^c * 7^d * ..., the number of factors is (a+1)(b+1)(c+1)(d+1)...


Do you know how to prove that

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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby dyaomaster » Sun May 19, 2019 2:38 pm

basically there’s (a+1) ways to select how many 2’s are in the prime factorization of the factor, (b+1) for how many 3’s, etc.

oh yeah can I ask a question now
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby Multiuniverse » Sun May 19, 2019 2:41 pm

dyaomaster wrote:basically there’s (a+1) ways to select how many 2’s are in the prime factorization of the factor, (b+1) for how many 3’s, etc.


Oh
Ok
Makes sense
I forgot that you can choose to not add a number into the mix

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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby dyaomaster » Sun May 19, 2019 2:43 pm

okay question

Find the area of pentagon ABCDE, given that AB = BC = DE = 1, CD = AE = sqrt(2), and points A, C, and E are collinear.
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby ZoruaLuhansk » Mon May 20, 2019 3:39 pm

Multiuniverse wrote:
ZoruaLuhansk wrote:
DestructionII wrote:
ZoruaLuhansk wrote:look at the number sqrt(2)^sqrt(2)
if it is rational, we've solved our problem
if it is irrational, then (sqrt(2)^sqrt(2))^sqrt(2) = sqrt(2)^2 = 2 does

If in triangle ABC, AB = 2sqrt(2), BC = 7, and AC = 4sqrt(2), what is the length of the median from A to BC?


Forgot to answer this one, oops lol.

I don't quite know this one, but I think you gotta find the value of: 2sqrt(2)+7, then find the midpoint of that value, so I'm assuming the answer is 4.914 - Oops if I got that wrong

Suppose you have 2 copies of triangle ABC
if you rotate the second one 180 degrees and stick the two BC's together, you get a paralellogram
In a paralellogram, the sum of the squares of the sides is equal to the sum of the squares of the diagonals
one diagonal has length 7, the other has length 2*the median we want
2*AB^2 + 2*AC^2 = BC^2 + (2x)^2
16 + 64 = 49 + (2x)^2
(2x)^2 = 31
x = sqrt(31)/2

Suppose p(x) is the product of all of the factors of x. For example, p(6) = 1 * 2 * 3 * 6 = 36.
If p(p(p(p(10)))) = 10^n, what is the largest prime factor of n?


p(x) would be x^(no. of factor/2). In the case that no. of factor is odd minus that by 1 then times the whole thing by x (because the odd one is sqrt(x))

Therefore since 10 has 4 factors (1, 2, 5, 10), p(10) is 10^(4/2) = 10^2
p(p(10)) would be p(100). 100 has 9 factors. Therefore p(100) is 100^(8/2) x 10 = 10^9
p(p(p(10)) would be p(10^9). 10^9 has ? factors

I got this far then got stuck at how many factors 10^9 has
I could probably manually do it by matching 5^9 and 2^9 but cba

I hate number theory and geometry
Also statistics


10^9 has 100 factors
so we get 10^(900/2) = 10^450
10^450 has 451^2 factors
so we get 10^(450*451^2 / 2) = 10^(3^2 * 5^2 * 11^2 * 41^2)
so the answer is 41
refer to the above post for the problem to solve
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Re: The Ultimate Math Game !! [{COME CHECK IT OUT!}]

Postby dyaomaster » Mon Jun 03, 2019 10:10 pm

dyaomaster wrote:okay question

Find the area of pentagon ABCDE, given that AB = BC = DE = 1, CD = AE = sqrt(2), and points A, C, and E are collinear.


bump
can I do that
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