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Count in threes

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Count in threes

Postby dyaomaster » Sat Aug 26, 2017 9:17 pm

Basically count from 1 to infinity.

But each number has to be expressed as some equation using only 3.


I'll start.

3/3 (=1)


(If you're stuck, use the post count!)
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Re: Count in threes

Postby qwertyuiopl » Sat Aug 26, 2017 10:14 pm

(3/3*3)*(3+3)
=(1/3)*6
=2
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Re: Count in threes

Postby lemonader666 » Sun Aug 27, 2017 6:25 am

3/3 + 3
= 1 + 3
= 4

Also what does "use the post count" mean?

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Re: Count in threes

Postby QnSb » Sun Aug 27, 2017 7:15 am

3! - 3 / 3
= 6 - 1
= 5
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Re: Count in threes

Postby qwertyuiopl » Sun Aug 27, 2017 7:28 am

(3^3)-([3+3]*[3+{3/3}])+3
=27-(6*4)+3
=27-24+3
=3+3
=6
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Re: Count in threes

Postby Edeneric » Sun Aug 27, 2017 10:37 am

3 divided by 3 + 3 + 3 = 7
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Re: Count in threes

Postby dyaomaster » Sun Aug 27, 2017 10:54 am

3 *!3 - 3/3 = 8
"use pose count" means that the post count represents what number the last person counted.
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Re: Count in threes

Postby qwertyuiopl » Sun Aug 27, 2017 4:42 pm

3*3=9
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Re: Count in threes

Postby lemonader666 » Sun Aug 27, 2017 7:29 pm

3^2 - (3*5 + 3/3)
=27 - (15 + 1)
=27 - 16
=11

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Re: Count in threes

Postby JazzMusicStops » Mon Aug 28, 2017 8:40 am

3+3+3+3 =12
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Re: Count in threes

Postby dyaomaster » Mon Aug 28, 2017 8:43 am

3*3+3+3/3 = 13
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Re: Count in threes

Postby JazzMusicStops » Mon Aug 28, 2017 8:44 am

3*3 + 3 + 3 - 3/3 = 14
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Re: Count in threes

Postby lemonader666 » Mon Aug 28, 2017 8:50 am

3*5=15

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Re: Count in threes

Postby dyaomaster » Mon Aug 28, 2017 8:56 am

Lemon you're doing it wrong.

3(3+3-3/3)+3/3=16
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Re: Count in threes

Postby qwertyuiopl » Tue Aug 29, 2017 4:24 am

(3^3)-3!-3-(3/3)=17
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Re: Count in threes

Postby JazzMusicStops » Tue Aug 29, 2017 5:04 am

(3+3)*3 = 18
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Re: Count in threes

Postby dyaomaster » Wed Aug 30, 2017 6:31 pm

(3-3/3)(3*3+3/3)-3/3=19
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Re: Count in threes

Postby JazzMusicStops » Thu Aug 31, 2017 3:11 am

(3*3*3) - (3*3-3) - (3/3)
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Re: Count in threes

Postby deathghost12 » Thu Aug 31, 2017 9:04 pm

3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3-3^3^3^3^3^3^3^3-3^3^3^3^3^3^3-3^3^3^3^3^3^3-3^3^3^3^3^3-3^3^3^3^3^3-3^3^3^3^3-3^3^3^3^3-3^3^3^3-3^3^3^3-3-3
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Re: Count in threes

Postby Multiuniverse » Fri Sep 01, 2017 3:34 am

The area between the curve x^2+2x and the x-axis in the domain 0 <= x <= 10 when <= is less then or equal to.

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Re: Count in threes

Postby lemonader666 » Fri Sep 01, 2017 4:55 am

3^3 - 3

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Re: Count in threes

Postby deathghost12 » Fri Sep 01, 2017 8:11 am

(Base 4)
33+log(30 +3/3)+33
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Re: Count in threes

Postby dyaomaster » Fri Sep 01, 2017 8:13 am

(3+3-3/3)(3+3-3/3)=25

Please use base 10.
And only use 3's in your equation.

3^3-3/3=26
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Re: Count in threes

Postby deathghost12 » Fri Sep 01, 2017 8:17 am

Those were 3's in base 4 but okay base 10.
3^3
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Re: Count in threes

Postby Shilster » Fri Sep 01, 2017 8:43 am

3(3*3-3) + 3(3+3/3) + 3(-3/3) + (3/3)
= 3(9-3) + 3(3+1) + 3(-1) + 1
= 3(6) + 3(4) - 3 + 1
= 18 + 12 - 2
= 30 - 2
= 28
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